1. Introduction

4.GENERAL METHODS OF CALCULATION OF HEAT EXCHANGERS

4.1. Method of factor F

4.1.2. Example 1

You want to cool 4500 kg / h of an aqueous solution coming from an evaporator from 353 K to 313 K with 18000 kg / h of water at a temperature of 303 K. The heat capacity of dissolution (Cpdiss) is equal to the heat capacity of water (= Cpaigua 1Kcal/Kg ° C). If the global coefficient of heat transmission is 3300 KJ / h · m2 · h, calculate the following sections for a heat exchanger shell and tubes 2-4:

a) Find the value of the heat transferred (q).

b) Find the value of the factor F.

c) Find the area of transmission of heat required (A).


2. Configurations of heat exchangers
3. Calculation of concentric tubes heat exchangers
4. General methods of calculation of heat exchangers
  4.1. Method of factor F
    4.1.1. Graphs of factor F for different equipment
    4.1.2. Example 1
    4.1.3. Example 2
  4.2. Method ε-NTU

5. Test

6. Nomenclature
7. References

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