4. GENERAL METHODS OF CALCULATION OF HEAT EXCHANGERS

4.1. Method of factor F

4.1.3. Example 2

You want to heat 1000 kg / h of ethylene glycol from 293 K to 323 K in a heat exchanger shell and tubes 1-2, using fluid heating oil to 353 K. The oil circulates through the shell and exits to 329 K. Answer the following sections:

a) Calculate the heat transferred (q) and the necessary flow of mineral oil (W1).

b) Calculate U₀A₀ with the information above.

c) If you double the mass flow of two fluids, keeping the temperature input, raise heat balances and found ΔTlog.

d) Find the temperature of the two output currents, with the information above.

INFORMATION:

C_{p ethylene glycol} = 2,557 KJ/Kg K

C_{p oil} = 2,1313 KJ/Kg K

Suppose that the thickness and resistance to the wall opposite the transfer of heat is negligible.
The surface convection coefficients are proportional to its mass flow:

h_i = AW_i; h₀ = BW₀; where A and B are constants.